(x+3)^2=(x-3)(x-3+16)

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Solution for (x+3)^2=(x-3)(x-3+16) equation: 



(x+3)^2=(x-3)(x-3+16)

We move all terms to the left:

(x+3)^2-((x-3)(x-3+16))=0

We add all the numbers together, and all the variables

(x+3)^2-((x-3)(x+13))=0

We multiply parentheses ..

-((+x^2+13x-3x-39))+(x+3)^2=0



We calculate terms in parentheses: -((+x^2+13x-3x-39)), so:

(+x^2+13x-3x-39)

We get rid of parentheses

x^2+13x-3x-39

We add all the numbers together, and all the variables

x^2+10x-39

Back to the equation:

-(x^2+10x-39)



We get rid of parentheses

-x^2-10x+(x+3)^2+39=0

We add all the numbers together, and all the variables

-1x^2-10x+(x+3)^2+39=0

We move all terms containing x to the left, all other terms to the right

-1x^2-10x+(x+3)^2=-39

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